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If the coefficient of friction between `A` and `B` is `mu`, the maximum acceleration of the wedge `A` for which `B` will remain at rest with respect to the wedge is
image
A. `mug`
B. `g((1+mu)/(1-mu))`
C. `g((1-mu)/(1+mu))`
D. `(g)/(mu)`

1 Answer

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Correct Answer - B
(b) `N sin theta+ mu N cos theta=ma`
image
`N cos theta+ mu N sin theta=ma`
Putting `theta=45^(@)` and solving these two equations , we get
`a=g((1+mu)/(1-mu))`

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