Question

A man of mass `m` stands on a platform of equal mass `m` and pulls himself by two ropes passing over pulleys as shown in figure.If he pulls each rope with a force equal to half his weight ,his upwards acceleration would be

A. `(g)/(2)`
B. `(g)/(4)`
C. g
D. zero

Answer 1

Correct Answer - D
(d) Total upward force`=2((mg)/(2))=mg`
[Weight of man is balanced by total tension acting upwards]
Total downward force is also mg
`therefore " " F_("net")=0=a_("net")`