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A block of mass m slides down an inclined plane which makes an angle `theta` with the horizontal. The coefficient of friction between the block and the plane is `mu`. The force exerted by the block on the plane is
A. `mu mg`
B. `mu mg sin theta`
C. `mu (mg sin theta-mg cos theta)`
D. `mg sin theta`

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Correct Answer - D
(d) Block is a rest. Hence, `f=mg sin theta`
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