Question

In the diagram shown in figure, match the following `(g=10 m//s^(2))`

`{:(,"Column-I",,,"Coloumn-II"),((A),"Acceleration of 2kg block",,(P), "8 Si unit"),((B),"Net force on 3kg block",,(Q),"25 SI unit"),((C),"Normal reaction between 2 kg and 1kg",,(R),"2 SI unit"),((D),"Normal reaction between 3 kg and 2kg " ,,(S)," 45 SI unit"),(,,,(T)," None"):}`

Answer 1

Correct Answer - A`rarr`r,B`rarr`t,C`rarr`q,D `rarr`t
Acceleration of system,
`a=(60-18-(m_(1)+m_(2)+m_(3))g sin 30^(@))/((m_(1)+m_(2)+m_(3))=2 ms^(-2)`
Net force on 3 kg block=`m_(3)a=6N`
From free body diagram of 3 kg block, we have
`N_(12)-m_(1)g sin 30^(@)-18=m_(1)a implies N_(12)=25N`
From free body diagram of 3 kg block, we have
`60-m_(3)g sin 30^(@)-N_(32)=m_(3)a`
`therefore" " N_(12)=39N`