Question

A block is constrained to move along x-axis under a forc `F=4/(x^(2))(xne0)`. Here, F is in newton and x in metre. Find the work done by this force when the block is displaced from `x=4` m to `x=2m`.

Answer 1

Correct Answer - A
`W = int_(4)^(2)Fdx = int_(4)^(2)(4)/(x^(2))dx`
`= -4[(1)/(x)]_(4)^(2) = -4[(1)/(2) - (1)/(4)] = -1J`