Correct Answer - C
(c ) when the car is moving in a circular horizontal track of
radius 10 m with a constant speed, then the bob is also
undergoing a circular motion. The bob is under the influence
of two forces.
(i) T (tension in the rod)
(ii) mg(weith of the bob)
Resolving tension, we get
`T cos theta = mg ....(i)`
And `T sin theta = (mv^2)/(r ) ....(ii)`
(Here `T sin theta` is producing the necessary centripetal
force for circular motion)
Dividing (ii) by (i) we get
`tan theta = (v^2)/(rg) = (10xx10)/(10xx10) =1 rArr thet = 45^@.`