Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
694 views
in Physics by (84.4k points)
closed by
Two identical ladders, each of mass M and length L are resting on the rough horizontal surface as shown in the figure. A block of mass m hangs from P. if the system is in equilibrium, find the magnitude and the direction of frictional force at A and B.
image

1 Answer

0 votes
by (82.2k points)
selected by
 
Best answer
Correct Answer - A::B::C
The various forces acting on the ladders are shown in the
figure.
Sicce the system is in equilibrium, therefore
`SimgaF_y = 0`
`rArr Mg + mg+Mg = N+N
image
`rArr N = ((2M+m)g)/(2) ….(i)`
`rArr mgxx(L)/(2)cos theta + fxxLsin theta = NL cos theta `
`rArr f = (NL cos theta - (Mgl)/(2) cos theta)/(L sin theta)= N cot theta - (Mg)/(2) cot theta`
`rArr f = [(2N+m)/(2))g - (Mg)/(2)]cos theta`
`rArr f= [(M + m) (g)/(2)] cot theta`
image

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...