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in Physics by (87.4k points)
A bomb is fired from a cannon with a velocity of `1000 ms^(-1)` making an angle of `30^(@)` with the horizontal `(g = 9.8 ms^(-2))`, (i) What is the time taken by the bomb to reach the highest point ? (ii) What is the total time of its motion ? (iii) With what speed the bomb will hit the ground and what will be its direction of motion while hitting ? (iv) What is the maximum height attained by the bomb ? (v) At what distance from the cannon the bomb will hit the ground ?

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1 Answer

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Correct Answer - `[(i) 51 s (ii) 1002 s (iii) 1000 ms^(-1), " at "30^(@) " with the horizontal "(iv) 1.27 xx 10^(4) m (v) 8.83 xx 10^(4) m]`

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