Question

A rocket of mass `40kg` has `160kg` fuel. The exhaust velocity of the fuel is `2.0km//s`. The rate of consumption of fuel is `4kg//s`. Calculate the ultimate vertical speed gained by the rocket. `(g=10m//s^2)`

Answer 1

Correct Answer - A::B
Fuel is finished in `40s`
`v=u-"gt"+v_(r)1n(m_0/m)`
`=0-10xx40+(2xx10^3)1n(200/40)`
`=2818m//s=2.82km//s`