Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
868 views
in Physics by (84.4k points)
closed by
A string is wound round the rim of a mounted flywheel of mass `20 kg` and radius `20 cm`. A steady pull of `25 N` is applied on the cord. Neglecting friction and mass of the string, the angular acceleration of the wheel in `rad//s^(2)` is
A. `50`
B. `25`
C. `12.5`
D. `6.25`

1 Answer

+1 vote
by (82.2k points)
selected by
 
Best answer
image
`tau=Ialphaimplies25xx0.2=(1)/(2)xx20xx(0.2)^(2)alpha`
`alpha==12.5 rad//s^(2)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...