Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
116 views
in Physics by (87.4k points)
closed by
A light rod of length of length `2 m` is suspended from a ceiling horizontally by means of two vertical wires of equal length tied to its ends. One of the wires is made of steel and is of cross - section `10^(-3) m^(2)` and the other is of brass of cross- section `2xx10^(-3) m^(2).x` is the distance from the steel wire end, at which a weight may be hung. ` Y_(steel) = 2xx10^(11) Pa and Y_(brass) = 10^(11) Pa`
Which of the following statement(s) is /are correct ?

1 Answer

0 votes
by (76.0k points)
selected by
 
Best answer
Correct Answer - A::B::C
(a) Given, stress in steel =stress in brass
` T_(s)/A_(s)=T_(B)/A_(B )`
`T_(s)/T_B=A_(S)/A_(B)`
=`10^(-3)/(2xx10^(-3)) =1/2 `…(i)
As the system is in equilibrium, taking moments about D, we have
`T_(s.x)=T_(B)(2-x)`
:.` (T_(S))/(T_(B))=(2-x)/x ` .....(ii)
From Eq_s.(i) and (ii), We get `x=1.33m`
(b) `"Strain" = "stress"/Y`
Given, strain in steel = strain in brass
`:.(T_(s)//A_(s))/Y_(s)=(T_(B)//A_(B))/(Y_(B))`
`:.T_(S)/T_(B) =(A_(s)Y_(s))/(A_(B)Y_(B))=((1xx10^(-3))(2xx10^11))/((2xx10^(-3))(10^(11)) =1` .....(iii)
from Eq_s.(ii) and (iii), We have `x=1.0 m`
image

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...