Question

A metallic cube of side 10 cm is subjected to a shearing force of 300 kgf. The top force is displaced through 0.25 cm with respect ot the bottom ? Calculate the shearing strain produced .
A. 0.25
B. 2.5
C. 0.025
D. 0.08

Answer 1

Correct Answer - C
(c) Here, L=10 cm =`10xx10^(-2)` m
`DeltaL=0.25 cm =0.25xx10^(-2)m`
`therefore` Shearing strain `=(DeltaL)/(L)=(0.25xx10^(-2))/(10xx10^(-2))=0.025`