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in Physics by (84.4k points)
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A sphere of radius R is rolling on a rough horizontal surface. The magnitude of velocity of A with respect to ground will be
image
A. `sqrt(2)v_(CM)`
B. 2`V_(CM)sintheta`
C. `sqrt(2)v_(CM)sqrt(1+sintheta)`
D. No sufficient information

1 Answer

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Best answer
c) Here `v_(CM) = Romega`
`The resultant velocity of point A is
`v_(A) = sqrt(v_(CM)^(2) + (Romega)^(2) + 2v_(CM)(Romega)cos(90-theta))`
`=sqrt(v_(CM)^(2) + v_(CM)^(2) + 2v_(CM)^(2)sintheta)`
`sqrt(2)v_(CM)sqrt(1+sintheta))`
image

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