Question

The equation of a transverse wave propagating in a string is given by
`y = 0.02 sin (x + 30t)`
where, `x and y` are in second.
If linear density of the string is `1.3 xx 10^(-4)kg//m`, then the tension in the string is
A. `0.12N`
B. `1.2N`
C. `12 N`
D. `120 N`

Answer 1

Correct Answer - A
`v=(omega)/(k) = sqrt((T)/(mu)`
`:. T =mu((omega)/(k))^(2) =(1.3 xx 10^(-4))((30)/(1))^(2)`
`=0.12N`