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A horizontal stretched string, fixed at two ends, is vibrating in its fifth harmonic according to the equation, `t(x, t) = (0.01m) sin[(62.8m^(-1))t]`. Assuming `pi = 3.14`, the correct statement `(s)` is (are)
A. (a) The number of nodes is `5`
B. (b) The length of the string is `0.25m`
C. ( c ) The maximum displacement of the midpoint of the string, from its equilibrium position is `0.01m`
D. (d) The fundamental frequency is `100 Hz`

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Correct Answer - B::C
(b, c) `y = [0.01 sin(62.8x)] cos (628t)`.
image
`Length of string = 5 xx (1)/(20) = 0.25 m`
[ `because` `(2pi)/(lambda) = 62.8]`
The midpoint `M` is an antitode and has the maximum displacement `= 0.01m`
`The fundamental frequency = (v)/(21) = (omeag//k)/(21) = 20 Hz`

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