Question

What is the value of.
(a) `0^@ F` in Celsius scale ?
(b) (0 K) on fahrenheit scale ?

Answer 1

Correct Answer - A::B::C::D
(a) `(T_C - 0)/(100) = (T_F - 32)/(180)`
Putting `T_F = 0`, we get `T_C = -17.8^@ C`
(b) `(T_C - 0)/(100) = (T_F - 32)/(180)` or `(T_K -273)/(100) = (T_K - 32)/(180)`
putting `T_K = 0`, we get `T_F = -459.67^@ F`.