Question

The closed cylinder shown in figure has a freely moving piston separating chambers 1 and 2. Chamber 1 contains `25 mg` of `N_2` and chamber 2 contains `40 mg` of helium gas. When equilibrium is established what will be the ratio `L_1// L_2` ? What is the ratio of the number of moles of `N_2` to the number of moles of He ?(Molecular weights of `N_2` and He are 28 and 4. .

Answer 1

`n_1 = (0.025)/(28) = 8.89 xx 10^-4`
`n_2 = (0.04)/4 = 0.01`
`:. (n_1)/(n_2) = 0.089`
In equilibrium (p) and (T) are same.
`:. pV = n r T`
`:. V prop n or L prop n`
`:. (L_1)/(L_2) = (n_1)/(n_2) = 0.089`.