Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
184 views
in Physics by (87.4k points)
closed by
An air bubble of `20 cm^3` volume is at the bottom of a lake `40 m` deep where the temperature is `4^@ C`. The bubble rises to the surface which is at a temperature of `20 ^@ C`. Take the temperature to be the same as that of the surrounding water and find its volume just before it reaches the surface.

1 Answer

0 votes
by (76.0k points)
selected by
 
Best answer
Correct Answer - A::C
`n_1 = n_2`
`:. (p_1 V_1)/(R T_1) = (p_2 V_2)/(R T_2)`
`:. V_2 = (p_1 V_1 T_2)/(p_2 T_1) = ((p_0 + rho g h)V_1 T_2)/(p_0 T_1)`
= `((1.01 xx 10^5 + 10^3 xx 10 xx 40)(20)(273 +20))/(1.01 xx 10^5 (273 +4)`
=`105 cm^3`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...