Correct Answer - A::B::D
Using the relation of `(dm)/(dt)` derived in above example,
`(dm)/(dt) = (TD)/(RL) = ((TD)KA)/(lL)` `(as R= l/(KA))`
Given that,
`((dm)/(dt))_(RHS) = 2((dm)/(dt))_(LHS)`
or ` [((TD)KA)/(lL)]_(RHS) = 2[((TD)KA)/(lL)]_(LHS)`
K and A are same on both sides. Hence,
`((TD)/(lL))_(RHS) = 2((TD)/(lL))_(LHS)`
Substituting the proper values, we have
`((200)/(l_2xx80))=2[(100)/(l_1xx540)]`
`l_1/l_2 = 80/540= 4/27`