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If `y=(1)/(x^10)=x^-10`, then find `dy//dx`.

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If `y=(1)/(x^10)=x^-10`, then find `dy//dx`.
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Differentiating both sides w.r.t. x, using `(d[x^n])/(dx)=nx^(n-1)`,
we get
`(dy)/(dx)=(d[x^-10])/(dx)=-10x^(-10-1)=-10/x^11`
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