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The pitch of a screw gauge is `1 mm and there are 100 divisions` on the circular scale. In measuring the diameter of a sphere there are six divisions on the linear scale and forty divisions on circular scale coincide with the reference line. Find the diameter of the sphere.

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`LC = (1)/(100) =0.01 mm`
Linear scale reading ` =6("pitch") = 6mm`
Circular scale reading `=n(LC) = 40xx 0.01=0.4 mm`
Total reading `=(6 +0.4)=6.4 mm`.

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