Correct Answer - B
`y = r sin ( omega t - kx)`
Here `omega t = angle rArr omega = (1)/(T) = T^(-1)`
Similarly , `kx = angle rArr K = (1)/(x) = L^(-1)` :. (omega)/(k) = (T^(-1))/(L^(-1)) = LT^(-1)`
Or simply `omega//k` represents wave velocity.
`(omega)/(k) = ( 2 pi f)/( 2 pi//f) = f lambda = v` , where f is frequency.