Question

Find magnitude and direction cosines of the vector, `A= (3hati - 4hatj+5hatk).`

Answer 1

Correct Answer - A::B::C::D
`A or |A| = sqrt((3)^2 + (-4)^2 + (5)^2) = 5sqrt2 units`
Directions of cosines are,
`cos alpha = (A_x)/(A) = (3)/(5sqrt2`
`cos beta = (A_y)/(A) = (-4)/(5sqrt2) and `
`cos_gamma = (A_z)/(A) =(1)/(sqrt2)`