Question

In terms of potential difference `C`, electric current`I` , permittivity `epsilon_(0)`, permeability `mu_(0)` and speed of light `c`, the dimensionally correct equation `(s)` is `(are)`
A. `mu_(0)I_(2) = epsilon V^(2)`
B. `mu_(0) I = mu_(0) V`
C. `I = epsilon_(0) V`
D. `mu_(0) cI = epsilon_(0) V`

Answer 1

Correct Answer - A::C
`[V] = [M^(-1) L^(2) T^(-3) A^(-1)]`
`[I] = [A]`
`[c ] = [L^(1) T^(-1)]`
`[epsilon _(0)] = [ M^(-1) L^(-3) T^(4) A^(2)]`
`[mu_(0)] = [M^(1) L^(1) T^(-2) A^(-2)]`
Option`A`
`[mu_(0) I^(2)] = [M^(1) L^(1) T^(-2)], [E_(0) V^(2)] = [M^(1) L^(1) T^(-1)]`
Option `B`
`[epsilon_(0) I] = [M^(1) L^(-3) T^(4) A^(3)]`
`[mu_(0) V] = [ M^(2) L^(3) T^(-5) A^(-3)]`
Option `C`
`[I ] = [A]`
`[epsilon_(0) c V] = [A]`
Option `D`
`[ mu_(0) c I] = [M^(1) L^(2) T^(-3) A^(-1)]`
`[epsilon _(0) V] = [L^(-1) TA]`
Options A and C correct.