Question

A body covera `10 m` in the seconds second and `25 m` in finfth second of its motion. If the motion is uniformly accelerated, how farwill it go in the the seventh second?

Answer 1

`10=u+(a)/(2)(2xx2-1)` and `25=u+(a)/(2) (2xx5-1)`
Solving, we get `u=(5)/(2)m s^(-1), a= ms^(-2)`
`D_(7)=(5)/(2)+(5)/(2)[2xx7-1] =35 m`.