Question

A parachutist after bailing out falls 50m without friction. When parachute opens, it decelerates at `2m//s^2`. He reaches the ground with a speed of `3m//s`. At what height, did the bail out?

Answer 1

Velocity after `(50) m` fall, `u_(1)=sqrt(2gh) =sqrt(100) g`
`3^(2)=u_(1)^(2)+2xx(-2)h rArr 9=100g-4h`
`h=(100xx9.8-9)/(4) =242.72=243 m`
Net height `=243=50 =293 m`.