Velocity of rain with respect to boy
`vec v_("rain,boy") = vec v_("rain") - vec v_("boy") = vec v_("rain") + (- vec v_("boy"))`
At any time `t`, rain will appear to the boy as shown in (Fig. 5.111).
`tan theta = (at)/(v)`
Boy should hold his umbrella at an angle `theta` from the vertical
`:. tan theta = (at)/(v)`
To find the rate at which the angle of the axis of umbrella with vertical, we need to find `d theta//dt`.
`(d tan theta)/( dt) = d (((at)/(v)))/(d t) rArr sec^2 theta (d theta)/(dt) = (a)/(v)`
`rArr (d theta)/(d t) = (a)/(v sec^2 theta) = (a)/(v [ 1+ tan^2 theta])`
=`(a)/(v[1 + (a^2 t^2)/(v^2)]] = (av)/(v^2 + a^2 t^2)`
=`(2 xx 2)/(4 + 4 t^2) = (1)/(1 + t^2)`
`rArr (d theta)/(d t) = (1)/(1 + t^2)`.
![image](https://learnqa.s3.ap-south-1.amazonaws.com/images/161037864810780000021610378648.png)
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