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Consider the reaction C + D → Products. The rate of the reaction increases by a factor of 4 when the concentration of C is doubled. The rate of the reaction is tripled when concentration of D is tripled. What is the order of the reaction? Write the rate law.

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Given : 

C + D → Products OR xC + yD → Products

(i) When the concentration of C is doubled, 

The rate of the reaction increases by 4.

[C]2(final) = 2[C]1(initial) then R2(final) = 4R1(initial) 

(In this, the concentration of D is assumed to be constant.)

Hence, 

The reaction is second order in C.

∴ nc = 2

(ii) When the concentration of D is tripled, 

Rate is tripled. 

The concentration of C is assumed to be constant.

Hence,

The reaction is first order in D.

Rate law : Rate = A[C]2[D]

∴ (i) Order of the reaction = 3

(ii) Rate law : Rate = A[C]2[D]

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