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If three resistors 15Ω, 3Ω and 4Ω each are connected in series, what is the effective resistance in the circuit?

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Given: 

R1 =15Ω 

R2 = 3Ω 

R3 = 4Ω

Effective resistance in series (Rs) = ?

Rs = R1 + R2 + R3 

Rs = 15 + 3 + 4 

Rs = 22Ω

The effective resistance in the circuit is 22Ω.

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