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If `vecA=3hati+4hatj` and `vecB=7hati+24hatj`, find a vector having the same magnitude as `vecB` and parallel and same direction as `vecA`.

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The vector parallel to `vecA` and having magnitude
of `vecB` is `vecC=|vecB|hatA`
`B=sqrt(7^(2)+24^(2))=25`
`hatA=(vecA)/(A)=(3hati+4hatj)/sqrt(3^(2)+4^(2))=(1)/(5)(3hatj+4hatj)`
`vecC=25xx(1)/(5)(3hati+4hatj)=15hati+20hatj`

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