Correct Answer - C
As `F_(ext)=0`, according to the law of conservation of momentum,
`vecP_1+vecP_2=const ant`.
but initially both the blocks were at rest, so
`vecP_1+vecP_2=0`, i.e., `vecP_2=-vecP_1`
i.e., at any instant, the two blocks will have momentum equal in magnitude but opposite in direction (through they may have different values of momentum at different positions).