Question

A single conservative force `F(x)` acts on a `1.0-kg` particle that moves along the x-axis. The potential energy `U(x)` is given by `U(x)=20+(x-2)^2` where x is in meters. At `x=5.0m`, the particle has a kinetic energy of `20J`.
Determine the equation of `F(x)` as a function of x.
A. (a) `F=2+x`
B. (b) `F=2+3x`
C. (c) `F=2(2-x)`
D. (d) `F=3+2x`

Answer 1

Correct Answer - C
`F(x)=-(dU)/(dx)=-2(x-2)=2(2-x)`