Correct Answer - D
Let the velocity at the point is `v_C`. Then for projectile motion from C to A,
`Rang e=v_csqrt((2(height))/(g))implies3R=v_csqrt((2xx2R)/(g))`
`impliesv_C=3/2sqrt(Rg)`
To find velocity at B, apply conservation of energy, i.e.,
`=1/2mv_B^2=mg2R+1/2mv_C^2=V_B=5/2sqrt(Rg)`