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The acceleration of a particle which moves along the positive x-axis varies with its position as shown in figure. If the velocity of the particle is `0.8 ms^(-1)` at x = 0, then velocity of the particle at `x = 1.4 m` is `(in ms^(-1))`.
image
A. 1.6
B. 1.2
C. 1.4
D. None of these

1 Answer

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Best answer
Correct Answer - B
b. `a = v(dv)/(dt) rArr int_(u)^(v) vdv = int_(0)^(1.4) adx`
`rArr (v^2-u^2)/2 = Area of a-x graph`
`rArr v^2 = (0.8)^2 = 2(0.4) rArr v = 1.2 ms^(-1)` .

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