Question

A particle starting from rest. Its acceleration (a) versus time (t) is as shown in the figure.
The maximum speed of the particle will be.

A. `110 ms^(-1)`
B. `55 ms^(-1)`
C. `550 ms^(-1)`
D. `660 ms^(-1)`

Answer 1

Correct Answer - B
Till 11 s, acceleration is positive, so velocity will happen at 11 s,
The area under the acceleration - time graph gives change in
velocity. Since particle starts with u = 0, change in velocity is
`V_f - V_i = V_(max) - 0 = Area under a-t graph`
or `v_(max) = 1/2 xx 10 xx 11 = 55 ms^(-1)`.