Correct Answer - `x=sqrt((mv^(2))/(12k))`
First considering an inelastic collision between `B` and `C`.
`2mv(m+2m)v_(B)`
`v_(B)=2/3v` velocity of (`B` and `C`)
Then velocity of centre of mass during maximum compression
`v_(CM)=(3mv)/(4m)=3/4v`
`1/2mv_(4)^(2)+1/23mv_((b+c))^(2)=1/24mv_(CM)^(2)+1/2kx^(2)`
Then substituting the value `x=sqrt((mv^(2))/(12k))`