Correct Answer - B
Let the ball strike the block with a speed `u_(1)`. Since the initial speed (speed before collision) of the block `=u_(2)=0` for the perfectly elastic collision
`m_(1)u_(1)=m_(1)v_(1)+m_(2)v_(2)`
`e=1=v_(1)/(v_(2)-v_(1))impliesv_(2)-v_(1)=u_(1)`
`0.5u_(1)=0.5v_(1)2.5v_(2)`
`u_(1)=-v_(1)+v_(2)impliesv_(2)=u_(1)/3=(sqrt(2gl))/3=20/3 ms^(-1)`