Correct Answer - D
`vecv_(cm)=(m_(1)vecv_(1)+m_(2)vecv_(2)+m_(3)vecv_(3))/(m_(1)+m_(2)+m_(3))`
`implies vecv_(cm)=("Total momentum")/("Total mass")`
here total momentum of system is zero beause momentum of each particle is same in magnitude and they are symmetrically oriented as shown.
So `vecp_(1)+vecp_(2)+vecp_(3)=0`