Question

A particle is moving in x-y plane with its x and y co-ordinates varying with time as, `x=2t and y=10t-16t^2.` Find trajectory of the particle.

Answer 1

Correct Answer - A
Given, `x=2t`
rArr `t=x/2`
Now, `y=10t-16t^2`
Substituting value of t in this equation we have,
`y=10(x/2)-16(x)^2`
or `y=5x-4x^2`
This is the required equation of trajectory of the particle. This is a quadratic equation. Hence,
the path of the particle is a parabola.