Correct Answer - A
COLM :
Along horizontal
`0 = m(u cos theta - v) -4 mv rArr v = (u cos theta)/(5)`
`:.` velocity of shell along horizontal w.r.t ground
`= u cos theta - (u cos theta)/(5) = (4)/(5) (u cos theta)`
Time. of flight `T = (2u sin theta)/(g)`
`:, x =` horizontal displacement
`= ((4)/(5)u cos theta) ((2u sin theta)/(g)) = (4u^(2) sin 2theta)/(5g)`