Correct Answer - C
As rods are uniform therefore center of mass of both rods will beat their geometrical centers. The coordinates of CM of first rod `C_(1)` are (L/2,0) and second rod `C_(2)` are (0,L)
`therefore` `x_(CM) = (M(L/2) + 2M(0))/(M+2M) = L/6`
`y_(CM) = ((M(0) + 2M(L))/(M + 2M) = (2L)/3`
Hence, coordinates of CM are `(L/6, (2L)/3)`