Question

A block of mass m moving at speed `upsilon` collides wilth another block of mass 2 m at rest. The lighter block comes to rest after the collision. Find the coefficient of restitution.
A. `1/2`
B. 1
C. `1/3`
D. `1/4`

Answer 1

Correct Answer - A
From conservation of linear momentum, we can see that velocity of 2m will become v/2 after collision (as mass is doubled)

Now, e = (Relative velocity of separation)/(Relative velocity of approach) = (v/2)/(v) = 1/2`