Question

A particle of mass m moving with velocity u makes an elastic one-dimentional collision with a stationary particle of mass `m`. They come in contact for a very small time `t_0`. Their force of interaction increases from zero to `F_0` linearly in time `0.5t_0`, and decreases linearly to zero in further time `0.5t_0` as shown in figure. The magnitude of `F_0` is

A. `(mu)/T`
B. `(2mu)/T`
C. `(mu)/(2T)`
D. None of these

Answer 1

Correct Answer - B
In one dimensional elastic collision, between two equal masses velocities are interchanged. Therefore, change in linear momentum of any of the particle will be mu. Now impulse or area under F-T graph gives the change in linear momenntum.

`therefore 1/2F_(0)T = mu`
or `F_(0) = (2mu)/(T)`