Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
104 views
in Physics by (76.0k points)
closed by
A man of mass M stands at one end of a stationary plank of length L, lying on a smooth surface. The man walks to the other end of the plank. If the mass of the plank is `M//3`, the distance that the man moves relative to the ground is
A. `(3L)/4`
B. `L/4`
C. `(4L)/5`
D. `L/3`

1 Answer

0 votes
by (87.4k points)
selected by
 
Best answer
Correct Answer - B
Let plank moves x distance in opposite direction. Then, displacement of man relative to ground will be, (L-x), Applying
`m_(B)x_(B) = m_(L)x_(L)` or `M(L-x) =M/3x`
Solving the equation we get, `x = (3L)4`
`therefore` Displacement of man relative to ground = L - (3L)/4 = L/4`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...