Question

If the velocity of a particle is given by `v=(180-16x)^((1)/(2))(m)/(s)`, then its acceleration will be

Answer 1

Acceleration, ` a =(dv)/(dt) = (dv)/(dx) xx (dx)/(dt) v (dv)/(dx)`
Givin, ` v^(2) =(18 0- 16 x) ,`
Diferentiating it ` w.r.t. x`, we have ` 2 v (d v)/(dx) =- 16`
So, acceleration, ` a =v (dv)/(dx) =- (16)/2 =- 8 m//s^(2)`.