Question

A uniform rod of length `1 m` and mass `2 kg` is suspended. Calculate tension `T` (in `N`) in the string at the instant when the right string snaps `(g = 10 m//s^(2))`.

Answer 1

Correct Answer - 5
`Mg-T=Ma_(y)` ………..i
`T(L/2)=(ML^(2))/12 alpha`……….ii

and `a_(y)=L/2alpha`…..iii
On solving we get
`T=(Mg)/4=5N`