Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
690 views
in Physics by (76.0k points)
closed by
A uniform solid sphere of radius `R`, rolling without sliding on a horizontal surface with an angular velocity `omega_(0)`, meets a rough inclined plane of inclination `theta = 60^@`. The sphere starts pure rolling up the plane with an angular velocity `omega` Find the value of `omega`.
image

1 Answer

0 votes
by (87.4k points)
selected by
 
Best answer
Correct Answer - `9/14omega_(0)`
Using the conservation of angular momentum about the point of contact with the inclined plane.
image
`2/5mR^(2)omega_(0)+mv_(0)Rcos60^(2)=7/5mR^(2)omega`
`2/5 mR^(2)omega_(0)+(momega_(0)R^(2))/2=7/5mR^(2)omega`
`9/10 mR^(2)omega_(0)=7/5mR^(2)omega`
`:. omega=9/14omega_(0)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...