Correct Answer - D
If the man completes one revolution relative to the table, then
`theta_(mt)=2pi`
`implies 2pi=theta_(m)-theta_(t)`
`2pi=theta_(m)t-omega_(t)t` (where `t` is the time taken)
`t=(2pi)/(omega_(m)-omega_(t))=(2pi)/(0.5-(-0.05))=(2pi)/0.55s`
Angular displacement of the table is
` theta_(t)=omega_(r)t=-0.05xx((2pi)/0055)`
`=-((2pi)/11)` radians
The table rotates through `2pi//11` radians clockwise.