Correct Answer - D
Distance travelled by hody in `5` second is the toatl area which the velocity-time graph encloses with time axis , given by
` S= area OABB_1 + area BCC_1 B_1` ltBrgt `+ area CDC_1 + area DEF`
` = (( 400 + 20)/2) + (2 -0) + 20 xx ( 3-2)`
` + 1/2 xx ( 4 - 3) xx 20 + 1/2 xx 5- 4 ) xx 20`
` = 60 + 20 + 10 + 10`
`= 100 m`.