Question

A loop and a disc have same mass and roll without slipping with the same linear velocity `v`. If the total kinetic energy of the loop is `8 J`, the kinetic energy of the disc must be.

Answer 1

Correct Answer - 6
Total kinetic energy of loop `=1/2Iomega+1/2Mv^(2)`
`=1/2(MR^(2)omega^(2))+1/2Mv^(2)=Mv^(2)=8j(given)`
Total kinetic energy of disc `=1/2Iomega^(2)+1/2Mv^(2)`
`-=1/2(1/2MR^(2))((v^(2))/(R^(2)))+1/2Mv^(2)=3/4Mv^(2)=3/4(8)=6J`